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Question: Answered & Verified by Expert
In Young’s double-slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single-slit diffraction pattern is :
PhysicsWave OpticsJEE MainJEE Main 2014 (19 Apr Online)
Options:
  • A 3
  • B 6
  • C 24
  • D 12
Solution:
2449 Upvotes Verified Answer
The correct answer is: 12
d= separation between 2 slits

a= slit width

β y = fringe width in YDSE &  β D = width of central maxima

βy=λDd=λD6.1aβD=2λDa

β D =2×6.1 β y

=12.2 β y

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