In Young’s double-slit experiment, the slit separation is 1 mm and the screen is at a distance of 1 m from the slit. For a monochromatic light of wavelength 500 nm , the distance of 3 rd minima from the central maxima is

Question

In Young’s double-slit experiment, the slit separation is 1 mm and the screen is at a distance of 1 m from the slit. For a monochromatic light of wavelength 500 nm , the distance of 3 rd minima from the central maxima is, 0.50 mm, 1.25 mm, 1.50 mm, 1.75 mm

MARKS App · Accepted Answer

Distance of n th minima from central bright fringe x n = 2 n - 1 λ D 2 d For n = 3 i.e., 3 rd minima x 3 = 2 × 3 - 1 × 5 0 0 × 1 0 - 9 × 1 2 × 1 × 1 0 - 3 = 5 × 5 0 0 × 1 0 - 6 2 = 1.25 × 1 0 - 3 m = 1.25 mm

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