Initially, a beaker has 100 g of water at temperature 90 ° C . Later another 600 g of water at temperature 20 ° C was poured into the beaker. The temperature, T of the water (in ° C ) after mixing is

Question

Initially, a beaker has 100 g of water at temperature 90 ° C . Later another 600 g of water at temperature 20 ° C was poured into the beaker. The temperature, T of the water (in ° C ) after mixing is,

MARKS App · Accepted Answer

Given, Mass of water at 90 o C = 100 g = 100 × 10 - 3 kg Mass of water at 20 ° C = 600 g = 600 × 10 - 3 kg From calorimetry 100 × 10 − 3 S w ( 90 ° C − T ° C ) = 600 × 10 − 3 S w ( T ° C − 20 ° C ) 90 − T = 6 T − 120 T = 210 7 = 30 ° C

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