Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Initially, a block of mass m is at rest on a frictionless floor and the spring is in a relaxed condition. One end of the spring is rigidly attached to the block and the other end is fixed to a wall. A constant force is applied on the block as shown in the figure. The maximum velocity of the block is

PhysicsWork Power EnergyJEE Main
Options:
  • A FmK
  • B F2mK
  • C F2mK
  • D 2FmK
Solution:
2855 Upvotes Verified Answer
The correct answer is: FmK



The block attains maximum speed when it passes through its equilibrium position.

F=Kx

x=FK

From work-energy theorem

-12 K KF2+FFK=12mvmax2

F22K=12mvmax2

vmax=FmK

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.