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Question: Answered & Verified by Expert
Initially charge on \( C_{1} \) is \( q_{0} \) and all other capacitors are uncharged. If switch is closed at \( t=0 \), then the charge on \( C_{4} \) after along time of closing the switch is,
PhysicsCapacitanceJEE Main
Options:
  • A \( q_{0} \)
  • B \( \frac{q 0}{2} \)
  • C \( \frac{q 0}{3} \)
  • D \( \frac{q 0}{4} \)
Solution:
1927 Upvotes Verified Answer
The correct answer is: \( \frac{q 0}{3} \)
In parallel, total charge distribution is the direct ratio of capacitance.
 
Hence, q4=q03.

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