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Initially $n$ identical capacitors are joined in parallel and are charged to potential $V$. Now they are separated and joined in series. Then
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The correct answer is:
Potential difference becomes $n V$ and energy remains the same.
Charge will not flow and potential difference across each capacitor will be $V$. Hence, total potential difference across the series combination will be $n V$.
Total energy will remain same as charge is not flowing.
Total energy will remain same as charge is not flowing.
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