Initially the molar ratio of N 2 and H 2 was 1 : 3. At equilibrium, 50% of each has reacted. If the equilibrium pressure is P, the partial pressure of N H 3 at equilibrium is

Question

Initially the molar ratio of N 2 and H 2 was 1 : 3. At equilibrium, 50% of each has reacted. If the equilibrium pressure is P, the partial pressure of N H 3 at equilibrium is, P 3, P 4, P 6, P 8

MARKS App · Accepted Answer

Σ n = 0.5 + 1.5 + 1 = 3 Mole fraction of ammonia = x NH 3 = moles of ammonia total moles . P N H 3 = x N H 3 × P = 1 3 × P = P 3

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