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Question: Answered & Verified by Expert
\(\int \frac{\sin ^8 x-\cos ^8 x}{1-2 \sin ^2 x \cos ^2 x} d x\)
MathematicsIndefinite IntegrationWBJEEWBJEE 2011
Options:
  • A \(-\frac{1}{2} \sin 2 x+C\)
  • B \(\frac{1}{2} \sin 2 \mathrm{x}+\mathrm{C}\)
  • C \(\frac{1}{2} \sin x+C\)
  • D \(-\frac{1}{2} \sin x+C\)
Solution:
1145 Upvotes Verified Answer
The correct answer is: \(-\frac{1}{2} \sin 2 x+C\)
Hints: \(\int\left(\sin ^2 x-\cos ^2 x\right) d x=-\int \cos ^{2 x} d x=-\frac{1}{2} \sin 2 x+C\)

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