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Integrate the function
$\sqrt{4-x^2}$
$\sqrt{4-x^2}$
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Verified Answer
Let $I=\int \sqrt{4-x^2} d x=\int \sqrt{(2)^2-x^2} d x$ $=\frac{x \sqrt{4-x^2}}{2}+2 \sin ^{-1}\left(\frac{x}{2}\right)+C$
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