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Integrate the function
$\frac{\sin x}{\sin (x-a)}=\mathrm{I}(\mathrm{say})$
$\frac{\sin x}{\sin (x-a)}=\mathrm{I}(\mathrm{say})$
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$\begin{aligned} \mathrm{I} &=\int \frac{\sin (\overline{x-a}+a)}{\sin (x-a)} d x \\ &=\int \frac{\sin (x-a) \cos a+\cos (x-a) \sin a}{\sin (x-a)} d x \\ &=x \cos a+\sin a \log \sin (x-a)+C \end{aligned}$
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