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Integrate the function
$\sqrt{x^2+4 x-5}$
$\sqrt{x^2+4 x-5}$
Solution:
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Verified Answer
$\int \sqrt{x^2+4 x-5} d x=\int \sqrt{(x+2)^2-(3)^2} d x$
$=\frac{x+2}{2} \sqrt{x^2+4 x-5}-\frac{9}{2} \log \left|x+2+\sqrt{x^2+4 x-5}\right|+C$
$=\frac{x+2}{2} \sqrt{x^2+4 x-5}-\frac{9}{2} \log \left|x+2+\sqrt{x^2+4 x-5}\right|+C$
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