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Question: Answered & Verified by Expert
Integrate the function
$\frac{3 x^2}{x^6+1}$
MathematicsIntegrals
Solution:
2088 Upvotes Verified Answer
Let $x^3=t \Rightarrow 3 x^2 d x=d t$
$\int \frac{3 x^2}{x^6+1} d x=\int \frac{d t}{t^2+1}=\tan ^{-1} t+\mathrm{C}=\tan ^{-1}\left(x^3\right)+\mathrm{C}$

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