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Integrate the function
$x \sec ^2 x$
$x \sec ^2 x$
Solution:
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Verified Answer
$\int x \sec ^2 x d x=x(\tan x)-\int 1 \cdot \tan x d x$
$=x \tan x+\log \cos x+C$
$=x \tan x+\log \cos x+C$
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