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Question:
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Integrate the function
$x \sin x$
$x \sin x$
Solution:
2010 Upvotes
Verified Answer
By part integration,
$\begin{aligned}
&\int x \sin x d x=x(-\cos x)-\int 1(-\cos x) d x \\
&=-x \cos x+\int \cos x d x=-x \cos x+\sin x+C
\end{aligned}$
$\begin{aligned}
&\int x \sin x d x=x(-\cos x)-\int 1(-\cos x) d x \\
&=-x \cos x+\int \cos x d x=-x \cos x+\sin x+C
\end{aligned}$
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