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Intensities of the two waves of light are $I$ and $4 I$. The maximum intensity of the resultant wave after superposition is
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The correct answer is:
$91$
$I_{\max }=I_1+I_2+2 \sqrt{I_1 I_2}$
So, $I_{\max }=I+4 I+2 \sqrt{I .4 I}=9 I$
So, $I_{\max }=I+4 I+2 \sqrt{I .4 I}=9 I$
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