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Internal energy and pressure of a gas per unit volume are related as
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The correct answer is:
$P=\frac{2}{3} E$
$K E=\frac{3}{2} R T=\frac{3}{2} P V$
$\therefore P=\frac{2}{3} \frac{E}{V}$ for unit volume $(V=1) \Rightarrow P=\frac{2}{3} E$
$\therefore P=\frac{2}{3} \frac{E}{V}$ for unit volume $(V=1) \Rightarrow P=\frac{2}{3} E$
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