Intersection of two perpendicular tangents to the hyperbola $\frac{x^2}{4}-\frac{y^2}{2}=1$ lies on the circle $x^2+y^2=\ldots \ldots \ldots$

Question

Intersection of two perpendicular tangents to the hyperbola $\frac{x^2}{4}-\frac{y^2}{2}=1$ lies on the circle $x^2+y^2=\ldots \ldots \ldots$, 2, 12, $\sqrt{2}$, $2 \sqrt{3}$

MARKS App · Accepted Answer

Locus of point of intersection of perpendicular tangents to hyperbola $\frac{x^2}{4}-\frac{y^2}{2}=1$ is the director circle $x^2+y^2=4-2=2$ Hence, option (a) is correct.

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