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\(\int_{-\pi}^\pi x^2(\sin x) d x=\)
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\(\int_{-\pi}^\pi x^2(\sin x) d x\)
\(x^2(\sin x)\) is an odd function
So, \(\int_{-\pi}^\pi x^2(\sin x) d x=0\)
\(x^2(\sin x)\) is an odd function
So, \(\int_{-\pi}^\pi x^2(\sin x) d x=0\)
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