Iodine is formed when potassium iodide reacts with a solution of, ZnSO 4 , CuSO 4 , ( NH 4 ) 2 SO 4 , Na 2 SO 4

CuSO 4 + 2 Kl ⟶ Cul 2 + K 2 SO 4 2 Cul 2 ⟶ Cuprous iodide 2 Cul + l 2

Iodine is formed when potassium iodide reacts with a solution of

Search any question & find its solution

Question: Answered & Verified by Expert

Iodine is formed when potassium iodide reacts with a solution of

Chemistryp Block Elements (Group 15, 16, 17 & 18)VITEEEVITEEE 2014

Options:

A $\mathrm{ZnSO}_{4}$
B $\mathrm{CuSO}_{4}$
C $\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}$
D $\mathrm{Na}_{2} \mathrm{SO}_{4}$

Solution:

2855 Upvotes Verified Answer

The correct answer is: $\mathrm{CuSO}_{4}$

$\mathrm{CuSO}_{4}+2 \mathrm{Kl} \longrightarrow \mathrm{Cul}_{2}+\mathrm{K}_{2} \mathrm{SO}_{4}$ $2 \mathrm{Cul}_{2} \longrightarrow \stackrel{2 \mathrm{Cul}+\mathrm{l}_{2}}{\text { Cuprous iodide }}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play