Ionic radius (in A ˚ ) of As 3 + , Sb 3 + and Bi 3 + follow the order

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Ionic radius (in $Å$ ) of $\mathrm{As}^{3+}, \mathrm{Sb}^{3+}$ and $\mathrm{Bi}^{3+}$ follow the order

ChemistryClassification of Elements and Periodicity in PropertiesTS EAMCETTS EAMCET 2001

Options:

A $\mathrm{As}^{3+}>\mathrm{Sb}^{3+}>\mathrm{Bi}^{3+}$
B $\mathrm{Sb}^{3+}>\mathrm{Bi}^{3+}>\mathrm{As}^{3+}$
C $\mathrm{Bi}^{3+}>\mathrm{As}^{3+}>\mathrm{Sb}^{3+}$
D $\mathrm{Bi}^{3+}>\mathrm{Sb}^{3+}>\mathrm{As}^{3+}$

Solution:

1062 Upvotes Verified Answer

The correct answer is: $\mathrm{Bi}^{3+}>\mathrm{Sb}^{3+}>\mathrm{As}^{3+}$

Ionic radius increases in a group from top to bottom i.e., it increases from $\mathrm{As}^{3+}$ to $\mathrm{Bi}^{3+}$.

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