Ionisation energy of He + is 19 .6 × 10 − 18 J per atom. The energy of the first stationary state (n = 1) of Li 2+ per atom is

Question

Ionisation energy of He + is 19 .6 × 10 − 18 J per atom. The energy of the first stationary state (n = 1) of Li 2+ per atom is, 4.41 × 10 − 16 J, 4.41 × 10 − 17 J, 2.2 × 10 − 15 J, 8.82 × 10 − 17 J

MARKS App · Accepted Answer

IE = Z 2 n 2 × 13 .6 eV …(i) IE 1 IE 2 = Z 1 2 n 1 2 × n 2 2 Z 2 2 …(ii) Given IE 1 = 19 .6 × 10 − 18 , Z 1 = 2, n 1 = 1, Z 2 = 3 and n 2 =1 . Substituting these values in equation (ii) 19 .6 × 10 − 18 IE 2 = 4 1 × 1 9 Or IE 2 = 19 .6 × 10 − 18 × 9 4 = 4 .41 × 10 − 17 J/atom

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