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Ionisation potential of hydrogen atom is $13.6 \mathrm{~V}$. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy $12.1 \mathrm{eV}$. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be
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three
Energy in the excited state $=-13.6+12.1$ $=-1.5 \mathrm{eV}$
$\therefore-\frac{13.6}{n^2}=-1.5$ or $n=\sqrt{\frac{13.6}{1.5}}=3$
$\therefore \quad$ Number of spectral lines
$$
=\frac{n(n-1)}{2}=\frac{3(3-1)}{2}=3
$$
$\therefore-\frac{13.6}{n^2}=-1.5$ or $n=\sqrt{\frac{13.6}{1.5}}=3$
$\therefore \quad$ Number of spectral lines
$$
=\frac{n(n-1)}{2}=\frac{3(3-1)}{2}=3
$$
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