Ionization energy of H e + ion at minimum energy position is

Question

Ionization energy of H e + ion at minimum energy position is, 13.6 e V, 27.2 e V, 54.4 e V, 68.0 e V

MARKS App · Accepted Answer

Energy of helium ions. E n = - 13 .6 Z 2 n 2 eV In minimum position, n = 1 . For He + , Z = 2 . E = - 13 .6 × ( 2 ) 2 1 eV E =- 54.4 eV Ionization Energy = - E = 54 . 4 eV

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