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Ionization potential of hydrogen atom is $13.6 \mathrm{eV}$. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy $12.1 \mathrm{eV}$. According to Bohr's theory, the spectral lines emitted by hydrogen will be:
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Verified Answer
The correct answer is:
three
According to question
$$
\begin{aligned}
& 12.1=13.6\left(\frac{1}{l^2}-\frac{1}{n^2}\right) \\
& \Rightarrow \quad n^2=\frac{13.6}{1.5}=9 \\
& \Rightarrow \quad n=3 \\
&
\end{aligned}
$$
Number of spectral lines emitted
$$
\begin{aligned}
& =\frac{n(n-1)}{2}=\frac{3 \times 2}{2} \\
& =3
\end{aligned}
$$
$$
\begin{aligned}
& 12.1=13.6\left(\frac{1}{l^2}-\frac{1}{n^2}\right) \\
& \Rightarrow \quad n^2=\frac{13.6}{1.5}=9 \\
& \Rightarrow \quad n=3 \\
&
\end{aligned}
$$
Number of spectral lines emitted
$$
\begin{aligned}
& =\frac{n(n-1)}{2}=\frac{3 \times 2}{2} \\
& =3
\end{aligned}
$$
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