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Question: Answered & Verified by Expert
Ionization power and penetration range of radioactive radiation increases in the order
PhysicsCurrent ElectricityVITEEEVITEEE 2007
Options:
  • A $\gamma, \beta, \alpha$ and $\gamma, \beta, \alpha$ respectively
  • B $\gamma, \beta, \alpha$ and $\alpha, \beta, \gamma$ respectively
  • C $\alpha, \beta, \gamma$ and $\alpha, \beta, \gamma$ respectively
  • D $\alpha, \beta, \gamma$ and $\gamma, \beta, \alpha$ respectively
Solution:
2080 Upvotes Verified Answer
The correct answer is: $\gamma, \beta, \alpha$ and $\alpha, \beta, \gamma$ respectively
$\alpha$ particles are positively charged He nucleus, it can accept $2 \mathrm{e}^{-}, \beta$ rays are negatively charged which are similar to $\mathrm{e}^{-}$, can donate $1 \mathrm{e}^{-}, \gamma$ are radiations. Hence ionisation power of $\alpha$ is maximum. $\gamma$ are most energetic and $\propto$ is least energetic $\therefore$ Penetration power of $\gamma$ is maximum.

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