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Iron (III) catalyses the reaction between iodide and persulphate ions, in which
A. \(\mathrm{Fe}^{3+}\) oxidises the iodide ion
B. \(\mathrm{Fe}^{3+}\) oxidises the persulphate ion
C. \(\mathrm{Fe}^{2+}\) reduces the iodide ion
D. \(\mathrm{Fe}^{2+}\) reduces the persulphate ion
Choose the most appropriate answer from the options given below:
Options:
A. \(\mathrm{Fe}^{3+}\) oxidises the iodide ion
B. \(\mathrm{Fe}^{3+}\) oxidises the persulphate ion
C. \(\mathrm{Fe}^{2+}\) reduces the iodide ion
D. \(\mathrm{Fe}^{2+}\) reduces the persulphate ion
Choose the most appropriate answer from the options given below:
Solution:
1483 Upvotes
Verified Answer
The correct answer is:
A and D only
$\begin{aligned} & 2 \mathrm{Fe}^{3+}+2 \mathrm{I}^{-} \longrightarrow 2 \mathrm{Fe}^{2+}+\mathrm{I}_2 \\ & 2 \mathrm{Fe}^{2+}+\mathrm{S}_2 \mathrm{O}_8^{2-} \longrightarrow 2 \mathrm{Fe}^{3+}+2 \mathrm{SO}_4^{2-}\end{aligned}$
$\mathrm{Fe}^{+3}$ oxidises $\mathrm{I}^{-}$to $\mathrm{I}_2$ and convert itself into $\mathrm{Fe}^{+2}$. This $\mathrm{Fe}^{+2}$ reduces $\mathrm{S}_2 \mathrm{O}_8{ }^{2-}$ to $\mathrm{SO}_4{ }^{2-}$ and converts itself into $\mathrm{Fe}^{+3}$.
$\mathrm{Fe}^{+3}$ oxidises $\mathrm{I}^{-}$to $\mathrm{I}_2$ and convert itself into $\mathrm{Fe}^{+2}$. This $\mathrm{Fe}^{+2}$ reduces $\mathrm{S}_2 \mathrm{O}_8{ }^{2-}$ to $\mathrm{SO}_4{ }^{2-}$ and converts itself into $\mathrm{Fe}^{+3}$.
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