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is equal to
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The correct answer is:
2
$\lim _{x \rightarrow \infty} x \sin \left(\frac{2}{x}\right)=\lim _{x \rightarrow 0} \frac{\sin \left(\frac{2}{x}\right)}{\frac{1}{2}\left(\frac{2}{x}\right)}=2$
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