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Question: Answered & Verified by Expert
It is because of the inability of ns2 electrons of the valence shell to participate in bonding that
Chemistryd and f Block ElementsNEETNEET 2017
Options:
  • A Sn2+ is reducing while Pb4+ is oxidizing.
  • B Sn2+ is oxidizing while Pb4+ is reducing.
  • C Sn2+ and Pb2+ are both oxidizing and reducing.
  • D Sn4+ is reducing while Pb4+ is oxidizing.
Solution:
2219 Upvotes Verified Answer
The correct answer is: Sn2+ is reducing while Pb4+ is oxidizing.
The inability of ns2 electrons of the valence shell to participate in bonding on moving down the group in heavier p-block elements is called inert pair effect.

As a result, Pb(II) is more stable than Pb(IV)

Sn(IV) is more stable than Sn(II)

    Pb(IV) is easily reduced to Pb(II).

    Pb(IV) is an oxidizing agent.

Sn(II) is easily oxidized to Sn(IV)

     Sn(II) is reducing agent.

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