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It is desired to photograph the image of an object placed at a distance of $3 \mathrm{~m}$ from the plane mirror. The camera which is at a distance of $4.5 \mathrm{~m}$ from the mirror should be focussed for a distance of
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The correct answer is:
$7.5 \mathrm{~m}$
The distance between the object and the mirror is $3 \mathrm{~m}$, i.e., $\mathrm{d} 1=3 \mathrm{~m}$,
Hence image distance also equals $\mathrm{d} 1=3 \mathrm{~m}$
Also, the distance between the mirror and the camera is $4.5 \mathrm{~m}$, i.e., $\mathrm{d} 2=4.5 \mathrm{~m}$.
Hence the focus of the camera,
$\mathrm{f}=\mathrm{d} 1+\mathrm{d} 2=3+4.5=7.5 \mathrm{~m}$
Hence image distance also equals $\mathrm{d} 1=3 \mathrm{~m}$
Also, the distance between the mirror and the camera is $4.5 \mathrm{~m}$, i.e., $\mathrm{d} 2=4.5 \mathrm{~m}$.
Hence the focus of the camera,
$\mathrm{f}=\mathrm{d} 1+\mathrm{d} 2=3+4.5=7.5 \mathrm{~m}$
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