It was calculated that a shell when fired from a gun with a certain velocity and at an angle of elevation 5 π 3 6 rad should strike a given target. In actual practice, it was found that a hill just prevented the trajectory. At what angle of elevation should the gun be fired to hit the target ?

Question

It was calculated that a shell when fired from a gun with a certain velocity and at an angle of elevation 5 π 3 6 rad should strike a given target. In actual practice, it was found that a hill just prevented the trajectory. At what angle of elevation should the gun be fired to hit the target ?, 5 π 3 6 rad, 1 1 π 3 6 rad, 7 π 3 6 rad, 1 3 π 3 6 rad

MARKS App · Accepted Answer

Ranges for complementary angles are the same R θ = R ( π 2 − θ ) ∴ Required angle = π 2 - 5 π 3 6 = 1 3 π 3 6 rad

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