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Question: Answered & Verified by Expert
k=040ik=x+iyx100+x99y+x242y2+x97y3=
MathematicsComplex NumberAP EAMCETAP EAMCET 2022 (04 Jul Shift 2)
Options:
  • A 0
  • B -4
  • C 4
  • D 1
Solution:
1214 Upvotes Verified Answer
The correct answer is: 1

Given:

k=040ik=x+iy

i0+i+i2+i3+i4+i5+i6+i7+i8+...+i37+i38+i39+i40=x+iy

i0+0=x+iy

x+iy=1

So, x=1, y=0

Therefore,

x100+x99y+x242y2+x97y3=1

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