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Question: Answered & Verified by Expert
K1 and K2 for oxalic acid are 6.5×102- and 6.1×10-5 respectively. What will be [HO-] in a 0.01 M solution of sodium oxalate?
ChemistryIonic EquilibriumNEET
Options:
  • A 9.6×10-6
  • B 1.4×10-1
  • C 1.28×10-6
  • D 1.3×10-8
Solution:
1940 Upvotes Verified Answer
The correct answer is: 1.28×10-6
The hydrolysis of C2O42- is represented by
C2O42-+H2OHC2O4-+OH-
Kh=KwK2=1.0×10-146.1×10-5=x20.01
So x=1.28×10-6

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