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Question: Answered & Verified by Expert
K2Cr2O7 paper acidified with dilute H2SO4 turns green when exposed to
Chemistryd and f Block ElementsJEE MainJEE Main 2023 (24 Jan Shift 2)
Options:
  • A Carbon dioxide
  • B Sulphur trioxide
  • C Hydrogen sulphide
  • D Sulphur dioxide
Solution:
1552 Upvotes Verified Answer
The correct answer is: Sulphur dioxide

Carbon dioxide and sulphur trioxide cannot undergo oxidation. Potassium dichromate is reduced to chromic sulphate in the presence of sulphur dioxide. The orange solution of potassium dichromate becomes green colour chromic sulphate.

K2Cr2O7 + 3SO2 + H2SO4  K2SO4 + Cr2(SO4)3 + H2O

Hence, the gas is sulphur dioxide.

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