K 2 H g I 4 is 55% ionized in aqueous solution. The value of Van't Hoff factor is

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K_{2} H g I_{4}

is

55%

ionized in aqueous solution. The value of Van't Hoff factor is

ChemistrySolutionsJEE Main

Options:

A 2.1
B 4.3
C 1.9
D 3.7

Solution:

1138 Upvotes Verified Answer

The correct answer is: 2.1

K_{2} H g I_{4} \to 2 K^{+} + H g {I_{4}}^{2 -}

\Rightarrow i = 1 + (n - 1) α

\Rightarrow i = 1 + (0 .55) (3-1) (∵ n = 3)

∴ i = 2.1

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