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$K$ is the force constant of a spring. The work done in increasing its extension from $I_1$ to $I_2$ will be
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$\frac{K}{2}\left(I_2^2-I_1^2\right)$
At extension $l_1$, the stored energy $=\frac{1}{2} K l_1^2$
At extension $l_2$, the stored energy $=\frac{1}{2} \mathrm{Nl}_2^2$
Work done in increasing its extension from $l_1$ to $l_2=\frac{1}{2} K\left(l_2^2-l_1^2\right)$
At extension $l_2$, the stored energy $=\frac{1}{2} \mathrm{Nl}_2^2$
Work done in increasing its extension from $l_1$ to $l_2=\frac{1}{2} K\left(l_2^2-l_1^2\right)$
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