K M n O 4 (mol. wt. = 158) oxidizes oxalic acid in acidic medium to C O 2 and water as follows 5 C 2 O 4 2 - + 2 M n O 4 - + 16 H + → 10 C O 2 + 2 M n 2 + + 8 H 2 O What is the equivalent weight of K M n O 4 ?

Question

K M n O 4 (mol. wt. = 158) oxidizes oxalic acid in acidic medium to C O 2 and water as follows 5 C 2 O 4 2 - + 2 M n O 4 - + 16 H + → 10 C O 2 + 2 M n 2 + + 8 H 2 O What is the equivalent weight of K M n O 4 ?, 158, 31.6, 39.5, 79

MARKS App · Accepted Answer

M n O 4 - + 8 H + + 5 e - → M n 2 + + 4 H 2 O Equivalent weight of K M n O 4 in acidic medium = m o l e c u l a r w e i g h t 5 = 158 5 = 31.6

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