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$\mathrm{KMnO}_4$ in alkaline medium changes to
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The correct answer is:
$\mathrm{MnO}_2$
In alkaline solution, $\mathrm{KMnO}_4$ is first reduced to manganate and then to insoluble manganese dioxide.
$\begin{aligned}
& 2 \mathrm{KMnO}_4+\mathrm{H}_2 \mathrm{O} \stackrel{\text { alkaline }}{\longrightarrow} 2 \mathrm{MnO}_2+2 \mathrm{KOH} \\
&+3[\mathrm{O}]
\end{aligned}$
$\begin{aligned}
& 2 \mathrm{KMnO}_4+\mathrm{H}_2 \mathrm{O} \stackrel{\text { alkaline }}{\longrightarrow} 2 \mathrm{MnO}_2+2 \mathrm{KOH} \\
&+3[\mathrm{O}]
\end{aligned}$
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