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$\mathrm{KMnO}_4$ on reaction with $\mathrm{KOH}$ does not give
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$\mathrm{MnO}_2$
$\begin{array}{r}2 \mathrm{KMnO}_4+2 \mathrm{KOH} \longrightarrow 2 \mathrm{~K}_2 \mathrm{MnO}_4+ \\ \mathrm{H}_2 \mathrm{O}+[\mathrm{O}]\end{array}$
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