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$\mathrm{KO}_2$, reacts with water to form $A, B$ and $C$.
$B$ forms $C$ when it reacts with iodine in basic medium. What are $B$ and $C$ respectively?
Options:
$B$ forms $C$ when it reacts with iodine in basic medium. What are $B$ and $C$ respectively?
Solution:
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Verified Answer
The correct answer is:
$\mathrm{H}_2 \mathrm{O}_2, \mathrm{O}_2$
(i) When $\mathrm{KO}_2$ reacts with water, it gives $(A)$,
$(B)$ and $(C)$ as follows:
(ii) When $(B)$, i.e. $\mathrm{H}_2 \mathrm{O}_2$ reacts with iodine in basic medium, it gives $(C)$, i.e. $\mathrm{O}_2$, as shown below :
$\because \mathrm{KOH}$ can not reduce $\mathrm{I}_2$, thus option (d) is the correct answer.
$(B)$ and $(C)$ as follows:
(ii) When $(B)$, i.e. $\mathrm{H}_2 \mathrm{O}_2$ reacts with iodine in basic medium, it gives $(C)$, i.e. $\mathrm{O}_2$, as shown below :
$\because \mathrm{KOH}$ can not reduce $\mathrm{I}_2$, thus option (d) is the correct answer.
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