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Question: Answered & Verified by Expert
limx0 sin2x2-1+cosx equals
MathematicsLimitsJEE MainJEE Main 2019 (08 Apr Shift 1)
Options:
  • A 42
  • B 22
  • C 2
  • D 4
Solution:
1537 Upvotes Verified Answer
The correct answer is: 42

limx0 sin2x2-1+cosx

On Rationalisation, we get,

     =limx0 sin2x2-1+cosx×2+1+cosx2+1+cosx

=limx0 2sinx2cosx221-cosx×2+1+cosx

=limx0 4sin2x2cos2x22sin2x2×2+1+cosx

=limx0 2cos2x22+1+cosx=2×22

=42.

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