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Question: Answered & Verified by Expert
limx0x+2sinxx2+2 sin x+1 - sin2x-x+1 is
MathematicsLimitsJEE MainJEE Main 2019 (12 Apr Shift 2)
Options:
  • A 3
  • B 1
  • C 2
  • D 6
Solution:
1494 Upvotes Verified Answer
The correct answer is: 2

limx0x+2sinxx2+2sinx+1sinxx+1   00form

By using L'Hospital Rule,

=limx01+2cosx12x+2cosx2x2+2sinx+11sin2x12sin2xx+1

=1+21+12=332=2.

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