Given: Latent heat of vaporization $L_v=22.6\times {10}^5 \mathrm{J} {\mathrm{kg}}^{-1}$

Mass of water, $m=100 \mathrm{kg}$ and temperature of vapour $T=100 °\mathrm{C}$.

The relation of heat and latent heat of vaporization is given as,$Q=m{L}_v$

$Q=100\times 22.6\times {10}^5=22.6\times {10}^7 \mathrm{J}$