lectronic configuration of $\mathrm{Cu}(\mathrm{II})$ is $3 \mathrm{~d}^9$ whereas that of $\mathrm{Cu}(\mathrm{I})$ is $3 \mathrm{~d}^{10}$. Which of the following is correct?

Question

lectronic configuration of $\mathrm{Cu}(\mathrm{II})$ is $3 \mathrm{~d}^9$ whereas that of $\mathrm{Cu}(\mathrm{I})$ is $3 \mathrm{~d}^{10}$. Which of the following is correct?, Stability of $\mathrm{Cu}(\mathrm{I})$ and $\mathrm{Cu}(\mathrm{II})$ depends on nature of copper salts, $\mathrm{Cu}(\mathrm{II})$ is more stable, $\mathrm{Cu}(\mathrm{I})$ and $\mathrm{Cu}(\mathrm{II})$ are equally stable, $\mathrm{Cu}$ (II) is less stable

MARKS App · Accepted Answer

Cu ( II ) is more stable than Cu ( I ) because hydration energy of Cu + 2 ion compensate IE 2 ​ of Cu .

Search any question & find its solution

Looking for more such questions to practice?