$\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ is paramagnetic while $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ is diamagnetic. Explain why?

Question

$\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ is paramagnetic while $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ is diamagnetic. Explain why?,

MARKS App · Accepted Answer

The presence of three unpaired electrons in $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ explains its paramagnetic character. $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ is diamagnetic, since there is no unpaired electrons.

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