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Question: Answered & Verified by Expert
Let ε0 denote the dimensional formula of the permittivity of vacuum. If M= mass, L= length, T= time and A= electric current, then dimensions of permittivity is given as M p L q T r A s . Find the value of p-q+rs
PhysicsUnits and DimensionsJEE Main
Solution:
1912 Upvotes Verified Answer
The correct answer is: 3
From Coulomb's law,
F=q1q24πε0r2
ε0=q1q24πFr2=(A1T1)(A1T1)[M1L1T-2][L2]=M-1L-3T4A2
p=-1,q=-3,r=4,s=2
p-q+rs=-1-(-3)+42=62=3

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