Let ∈ 0 denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then :

Question

Let ∈ 0 denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then :, ∈ 0 = M -1 L 2 T -1 A - 2, ∈ 0 = M -1 L 2 T -1 A, ∈ 0 = M -1 L - 3 T 2 A, ∈ 0 = M -1 L - 3 T 4 A 2

MARKS App · Accepted Answer

F = 1 4 π ε 0 q 1 q 2 R 2 ε 0 = q 1 q 2 4 π FR 2 Hence, ε 0 = C 2 N . m 2 = AT 2 ML T - 2 . L 2 = M -1 L - 3 T 4 A 2

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