Search any question & find its solution
Question:
Answered & Verified by Expert
Let $\sigma_1, \sigma_2$ be the standard deviations of two distributions $D_1$ and $D_2$ respectively and $D_1$ be more consistent than $D_2$. If the means of $D_1$ and $D_2$ are same, then the percentage increase in the standard deviation of $D_2$ over the standard deviation of $D_1$ is
Options:
Solution:
1047 Upvotes
Verified Answer
The correct answer is:
$\frac{\sigma_2-\sigma_1}{\sigma_1} \times 100$
Since mean of both the distribution are same, therefore
Percentage increase in the standard deviation of $D_2$ over the standard deviation of $D_1$
$$
=\frac{\sigma_2-\sigma_1}{\sigma_1} \times 100
$$
Percentage increase in the standard deviation of $D_2$ over the standard deviation of $D_1$
$$
=\frac{\sigma_2-\sigma_1}{\sigma_1} \times 100
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.