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Let $A=\{1,2,3\}, B=\{4,5,6,7\}$ and let $f=\{(1,4),(2,5),(3,6)\}$ be a function from $A$ to $B$. Show that $f$ is one-one.
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$$
\begin{aligned}
&A=\{1,2,3\}, B=\{4,5,6,7\} \\
&f=\{(1,4),(2,5),(3,6)\} .
\end{aligned}
$$
Every member of $\mathrm{A}$ has a unique image in $\mathrm{B}$
$\therefore \mathrm{f}$ is one-one
\begin{aligned}
&A=\{1,2,3\}, B=\{4,5,6,7\} \\
&f=\{(1,4),(2,5),(3,6)\} .
\end{aligned}
$$
Every member of $\mathrm{A}$ has a unique image in $\mathrm{B}$
$\therefore \mathrm{f}$ is one-one
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