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Let $A=\{1,2,3\}$. The number of equivalence relations containing $(1,2)$ is
(a) 1
(b) 2
(c) 3
(d) 4
(a) 1
(b) 2
(c) 3
(d) 4
Solution:
1951 Upvotes
Verified Answer
There are two equivalence relations containing $(1,2)$. i.e. $\mathrm{R}_1=\{(1,2),(1,1),(2,2),(3,3),(2,1)\}$ and
$$
R_2=\{(1,2),(1,1),(2,2),(3,3),(2,1),(1,3),(3,1),(2,3),(3,2)\}
$$
$$
R_2=\{(1,2),(1,1),(2,2),(3,3),(2,1),(1,3),(3,1),(2,3),(3,2)\}
$$
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