Let A = 2 b 1 b b 2 + 1 b 1 b 2 , where b 0 . Then the minimum value of det A b is:

Question

Let A = 2 b 1 b b 2 + 1 b 1 b 2 , where b > 0 . Then the minimum value of det A b is:, 2 3, - 2 3, 3, - 3

MARKS App · Accepted Answer

A = 2 b 1 b b 2 + 1 b 1 b 2 = 2 2 b 2 + 2 - b 2 - b 2 b - b + 1 b 2 - b 2 - 1 = 2 b 2 + 2 - b 2 - 1 = 2 b 2 + 4 - b 2 - 1 = b 2 + 3 A b = b + 3 b = b - 3 b 2 + 2 3 Hence, the minimum value of A b is 2 3 . ∵ b - 3 b 2 ≥ 0

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